Which of the following compounds forms a Na-s | vedclass

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Question

(A) The reaction with $NaNH_2$ (sodamide) is a characteristic test for terminal alkynes,which possess acidic hydrogen atoms.$NaNH_2$ is a strong base

Vedclass · Accepted Answer

$C_2H_2$

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(A) The reaction with $NaNH_2$ (sodamide) is a characteristic test for terminal alkynes,which possess acidic hydrogen atoms.$NaNH_2$ is a strong base that can abstract the acidic proton from the terminal alkyne to form a sodium acetylide salt.Among the given options,$C_2H_2$ (acetylene or ethyne) is a terminal alkyne with the structure $HC \equiv CH$.The reaction is: $HC \equiv CH + NaNH_2 \rightarrow HC \equiv C^-Na^+ + NH_3$.Therefore,$C_2H_2$ forms a $Na$-salt.

Which of the following compounds forms a $Na$-salt upon reaction with $NaNH_2$?

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