What is the correct order of reactivity towar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reactivity towards electrophilic substitution reaction $(ESR)$ depends on the electron density in the benzene ring.Aniline $(I)$ has an $-NH_2

Vedclass · Accepted Answer

$I > II > III$

Vedclass · Answer

(D) The reactivity towards electrophilic substitution reaction $(ESR)$ depends on the electron density in the benzene ring.Aniline $(I)$ has an $-NH_2$ group,which is a strong electron-donating group ($+M$ effect),increasing electron density and making it highly reactive.Benzene $(II)$ has no substituent,serving as the reference.Nitrobenzene $(III)$ has a $-NO_2$ group,which is a strong electron-withdrawing group ($-M$ effect),decreasing electron density and making it the least reactive.Therefore,the correct order of reactivity is $I > II > III$.

What is the correct order of reactivity towards electrophilic substitution for the compounds: Aniline $(I)$,Benzene $(II)$,and Nitrobenzene $(III)$?

Similar Questions

In benzene,the $1, 3$ position is called:

In the given reaction: $CH_3COCH_3 \xrightarrow{\text{Conc. } H_2SO_4, \text{Distillation}} [X]$. $[X]$ will be:

Suitable conditions to prepare hexachlorobenzene $(C_6Cl_6)$ from benzene $(C_6H_6)$ is/are:

Which of the following represents the Friedel-Crafts reaction?

When chlorine is passed through warm benzene in the presence of sunlight,the product obtained is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module