Arrange the following acids in decreasing ord | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The acidity of carboxylic acids depends on the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) stabili

Vedclass · Accepted Answer

$III > II > I$

Vedclass · Answer

(B) The acidity of carboxylic acids depends on the stability of the conjugate base (carboxylate ion).Electron-withdrawing groups ($-I$ effect) stabilize the conjugate base and increase acidity.The hybridization of the carbon atom attached to the carboxyl group determines the $-I$ effect strength: $sp > sp^2 > sp^3$.In $(III)$,the carbon is $sp$ hybridized (strongest $-I$ effect).In $(II)$,the carbon is $sp^2$ hybridized.In $(I)$,the carbon is $sp^3$ hybridized (weakest $-I$ effect).Therefore,the decreasing order of acidity is $III > II > I$.

Arrange the following acids in decreasing order of acidity:
$(I) CH_3CH_2COOH$
$(II) CH_2 = CH - COOH$
$(III) HC \equiv C - COOH$

Similar Questions

Ethyl acetate at room temperature is a

Identify the reagents $A$ and $B$ in the following reaction: $CH_3 CH_3 \leftrightarrow{(B)} CH_3 COOH \rightarrow{(A)} CH_3 CH_2 OH$

Toluene on reaction with the reagent $X$ gives $Y$,which dissolves in $NaHCO_3$ and when reacted with $Br_2 / Fe$ gives $Z$. What are $X$ and $Z$?

Identify the major product $Y$ from the following reaction:

Identify the structure of product $A$ in the following reaction:
$\text{Cyclohexanecarboxylic acid} \xrightarrow{LiAlH_4} A$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following acids in decreasing order of acidity:$(I) CH_3CH_2COOH$$(II) CH_2 = CH - COOH$$(III) HC \equiv C - COOH$