Find the number of optical isomers for the co | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given compound is an aldohexose (specifically glucose or its stereoisomers) with the structure $CHO-(CHOH)_4-CH_2OH$. There are $n = 4$ chiral

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(D) The given compound is an aldohexose (specifically glucose or its stereoisomers) with the structure $CHO-(CHOH)_4-CH_2OH$. There are $n = 4$ chiral carbon atoms in this molecule. The number of optically active isomers $(a)$ is given by $2^n = 2^4 = 16$. Since the molecule is asymmetric (the two ends are different,$CHO$ and $CH_2OH$),there are no meso compounds $(m = 0)$. Therefore,the total number of optical isomers is $2^n = 16$.

Find the number of optical isomers for the compound $CHO-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CH_2OH$.

Similar Questions

Which one given below is a non-reducing sugar?

Which reagent/s can be used to distinguish glucose and fructose?
$I$. Bromine water
$II$. Tollen's reagent
$III$. Schiff's reagent

Heating glucose with methanol in the presence of dry $HCl$ yields $\alpha$ and $\beta$ methyl glucosides. This indicates the presence of which of the following?

Stachyose is a

$D$-glucose and $D$-fructose can be differentiated by

Vedclass Test Series

Exam Paper Generator

Online Exam Module