How many stereoisomers does butane-2,3-diol h | vedclass

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(C) The structure of butane-$2,3$-diol is $CH_3-CH(OH)-CH(OH)-CH_3$.This molecule has two chiral centers $(n=2)$ and a plane of symmetry.The number of

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$3$

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(C) The structure of butane-$2,3$-diol is $CH_3-CH(OH)-CH(OH)-CH_3$.This molecule has two chiral centers $(n=2)$ and a plane of symmetry.The number of stereoisomers is calculated as follows:Total stereoisomers = $2^{n-1} + 2^{(n/2)-1} = 2^{2-1} + 2^{(2/2)-1} = 2^1 + 2^0 = 2 + 1 = 3$.These $3$ stereoisomers consist of one pair of enantiomers and one meso compound.Out of these,only $2$ are optically active (the enantiomeric pair).

How many stereoisomers does butane-$2,3$-diol have?

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