The electrophile NO_2^+ reacts with which of | vedclass

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(B) The electrophile $NO_2^+$ undergoes electrophilic aromatic substitution.Groups that are electron-withdrawing ($-I$ and/or $-M$ effect) deactivate

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$I, II$ and $III$

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(B) The electrophile $NO_2^+$ undergoes electrophilic aromatic substitution.Groups that are electron-withdrawing ($-I$ and/or $-M$ effect) deactivate the benzene ring and direct the incoming electrophile to the meta position.$(I)$ $-CCl_3$ is electron-withdrawing due to the $-I$ effect.$(II)$ $-NO_2$ is electron-withdrawing due to both $-I$ and $-M$ effects.$(III)$ $-CHO$ is electron-withdrawing due to both $-I$ and $-M$ effects.$(IV)$ $-O^-$ is a strongly electron-donating group due to the $+M$ effect,which activates the ring and directs to the ortho/para positions.Therefore,compounds $(I), (II),$ and $(III)$ are meta-directing.

The electrophile $NO_2^+$ reacts with which of the following compounds? In which case will $NO_2^+$ attack at the meta position?
$(I)$ $C_6H_5-CCl_3$
$(II)$ $C_6H_5-NO_2$
$(III)$ $C_6H_5-CHO$
$(IV)$ $C_6H_5-O^-$

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The electrophile $NO_2^+$ reacts with which of the following compounds? In which case will $NO_2^+$ attack at the meta position?$(I)$ $C_6H_5-CCl_3$$(II)$ $C_6H_5-NO_2$$(III)$ $C_6H_5-CHO$$(IV)$ $C_6H_5-O^-$