What is the possible number of stereoisomers | vedclass

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Question

(A) The given compound is $CH_3-CH=CH-CH(OH)-CH_3$ (pent-$3$-en-$2$-ol).It has one double bond $(C=C)$ that exhibits geometrical isomerism (cis/trans)

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) The given compound is $CH_3-CH=CH-CH(OH)-CH_3$ (pent-$3$-en-$2$-ol).It has one double bond $(C=C)$ that exhibits geometrical isomerism (cis/trans) and one chiral carbon atom $(C-2)$ that exhibits optical isomerism.Since the molecule is unsymmetrical,the total number of stereoisomers is calculated using the formula $2^n$,where $n$ is the number of stereocenters.Here,$n = 2$ (one double bond + one chiral center).Therefore,the total number of stereoisomers $= 2^2 = 4$.

What is the possible number of stereoisomers for the compound $CH_3-CH=CH-CH(OH)-CH_3$?

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