Arrange the following compounds in the correc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The acidic strength of carboxylic acids depends on the stability of the carboxylate ion formed after the loss of a proton.Electron-donating groups

Vedclass · Accepted Answer

$I > IV > II > III$

Vedclass · Answer

(C) The acidic strength of carboxylic acids depends on the stability of the carboxylate ion formed after the loss of a proton.Electron-donating groups (like alkyl groups) decrease acidity by destabilizing the carboxylate ion via the $+I$ effect.Electron-withdrawing groups (like the phenyl group) increase acidity by stabilizing the carboxylate ion via the $-I$ and resonance effects.Comparing the compounds:$(I) HCOOH$: No alkyl group attached.$(II) CH_3COOH$: Contains one methyl group ($+I$ effect).$(III) CH_3CH_2COOH$: Contains an ethyl group ($+I$ effect,stronger than methyl).$(IV) C_6H_5COOH$: Contains a phenyl group ($-I$ and resonance effect).Order of acidity: $HCOOH > C_6H_5COOH > CH_3COOH > CH_3CH_2COOH$.Thus,the correct order is $(I) > (IV) > (II) > (III)$.

Arrange the following compounds in the correct decreasing order of their acidic strength:
$(I) HCOOH$
$(II) CH_3COOH$
$(III) CH_3CH_2COOH$
$(IV) C_6H_5COOH$

Similar Questions

The reaction is given as: $CH_3COOCH_2CH_3 + Na^{18}OH \rightarrow (A) + (B)$.
Further,$(A) \rightarrow (C) + (D) \text{ (alcohol)}$.
Identify the product $(C)$.

When ethyl acetoacetate reacts with one mole of methyl magnesium iodide,the product of the reaction will be:

Which of the following is the strongest acid?

Bouveault-Blanc reduction reaction involves:

The major product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following compounds in the correct decreasing order of their acidic strength:$(I) HCOOH$$(II) CH_3COOH$$(III) CH_3CH_2COOH$$(IV) C_6H_5COOH$