Which of the following are secondary radicals?
$(1) \ CH_3 - \dot{C}H - C_2H_5$
$(2) \ CH_2 = \dot{C} - CH_3$
$(3) \ CH_2 = CH - \dot{C}H_2$
$(4) \ (CH_3)_2 \dot{C}H$

The stability of the following carbocations follows the order:
$I. (CH_3)_3C^{\oplus}$
$II. (CH_3)_2C^{\oplus}(OCH_3)$
$III. CH_3CH_2CH_2CH_2^{\oplus}$
$IV. CH_3CH^{\oplus}CH_2CH_3$

State True or False for the following statements:
$(i)$ Carbon possesses $sp^2$ hybridization in a carbocation.
$(ii)$ Carbon possesses $sp^3$ hybridization in a carbocation.
$(iii)$ $A$ carbocation is formed by homolytic fission of a bond.
$(iv)$ Carbocations are very stable.

The correct order of stability is:

Consider the following statements. Of these statements:
$(I) \ CH_3O-CH_2^+$ is more stable than $CH_3-CH_2^+$
$(II) \ Me_2CH^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(III) \ CH_2=CH-CH_2^+$ is more stable than $CH_3-CH_2-CH_2^+$
$(IV) \ CH_2=CH^+$ is more stable than $CH_3-CH_2^+$

Arrange the following carbanions in the decreasing order of stability:
$I. \ p-Br-C_6H_4-CH_2^-$
$II. \ C_6H_5-CH_2^-$
$III. \ p-CH_3O-C_6H_4-CH_2^-$
$IV. \ p-CHO-C_6H_4-CH_2^-$
$V. \ p-CH_3-C_6H_4-CH_2^-$
Choose the correct answer from the options given below: