In the reaction CH_3CN xrightarrow{H_3O^+, te | vedclass

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Question

(C) In the reactant $CH_3CN$ (acetonitrile),the functional carbon atom is the nitrile carbon $(C \equiv N)$. The hybridization of this carbon is $sp$

Vedclass · Accepted Answer

$sp$ to $sp^2$

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(C) In the reactant $CH_3CN$ (acetonitrile),the functional carbon atom is the nitrile carbon $(C \equiv N)$. The hybridization of this carbon is $sp$ because it forms two sigma bonds and two pi bonds.In the product $CH_3COOH$ (acetic acid),the functional carbon atom is the carboxyl carbon $(C=O)$. The hybridization of this carbon is $sp^2$ because it forms three sigma bonds and one pi bond.Therefore,the hybridization changes from $sp$ to $sp^2$.

In the reaction $CH_3CN \xrightarrow{H_3O^+, \text{heat}} CH_3COOH$,what is the change in the hybridization state of the functional carbon atom?

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