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(C) The structure of $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$. Monochlorination can occur at four different types of hydrogen atoms: $1$. At $C_1

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(C) The structure of $2$-methylbutane is $CH_3-CH(CH_3)-CH_2-CH_3$. Monochlorination can occur at four different types of hydrogen atoms: $1$. At $C_1$ (terminal methyl): $Cl-CH_2-CH(CH_3)-CH_2-CH_3$ (Achiral). $2$. At $C_2$ (tertiary carbon): $CH_3-CCl(CH_3)-CH_2-CH_3$ (Chiral,as $C_2$ is bonded to four different groups: $-CH_3, -Cl, -CH_2CH_3, -H$). $3$. At $C_3$ (secondary carbon): $CH_3-CH(CH_3)-CHCl-CH_3$ (Chiral,as $C_3$ is bonded to four different groups: $-CH_3, -Cl, -H, -CH_2CH_3$). $4$. At $C_4$ (terminal methyl): $CH_3-CH(CH_3)-CH_2-CH_2Cl$ (Achiral). Thus,there are $2$ chiral products obtained.

How many chiral products are obtained upon the monochlorination of $2$-methylbutane?

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