What is the correct order of basicity?

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Question

(A) The basicity of an anion is inversely proportional to the acidic strength of its conjugate acid.Conjugate acids are: $CH_3CH_3$ $(sp^3)$,$CH_2 = C

Vedclass · Accepted Answer

$CH_3CH_2^- > CH_2 = CH^- > HC \equiv C^- > OH^-$

Vedclass · Answer

(A) The basicity of an anion is inversely proportional to the acidic strength of its conjugate acid.Conjugate acids are: $CH_3CH_3$ $(sp^3)$,$CH_2 = CH_2$ $(sp^2)$,$HC \equiv CH$ $(sp)$,and $H_2O$.The acidic strength order of these conjugate acids is: $H_2O > HC \equiv CH > CH_2 = CH_2 > CH_3CH_3$.Therefore,the basicity order of their conjugate bases is: $CH_3CH_2^- > CH_2 = CH^- > HC \equiv C^- > OH^-$.

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