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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$1$. $[Cr(H_2O)_6]^{2+}$: $Cr^{2+}$ is $3d^4$

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$[Cr(H_2O)_6]^{2+} , [Fe(H_2O)_6]^{2+}$

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each complex:$1$. $[Cr(H_2O)_6]^{2+}$: $Cr^{2+}$ is $3d^4$. With a weak field ligand $(H_2O)$,$n = 4$.$2$. $[Fe(H_2O)_6]^{2+}$: $Fe^{2+}$ is $3d^6$. With a weak field ligand $(H_2O)$,$n = 4$.$3$. $[CoCl_4]^{2-}$: $Co^{2+}$ is $3d^7$. With a weak field ligand $(Cl^-)$,$n = 3$.$4$. $[Mn(H_2O)_6]^{2+}$: $Mn^{2+}$ is $3d^5$. With a weak field ligand $(H_2O)$,$n = 5$.Since $[Cr(H_2O)_6]^{2+}$ and $[Fe(H_2O)_6]^{2+}$ both have $n = 4$,they will have the same magnetic moment.

List-$I$ (Complex ion)	List-$II$ (Calculated spin only magnetic moment $(BM)$)
$A$. $[Cr(H_2O)_6]^{2+}$	$I$. $3.87$
$B$. $[Co(H_2O)_6]^{2+}$	$II$. $5.92$
$C$. $[Cu(H_2O)_6]^{2+}$	$III$. $4.90$
$D$. $[Mn(H_2O)_6]^{2+}$	$IV$. $1.73$

Which of the following pairs will have the same value of magnetic moment?

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