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(D) The reaction with $AgNO_3$ indicates that there are $2 \ mol$ of ionizable $Cl^-$ ions outside the coordination sphere.This is represented as $[Co

Vedclass · Accepted Answer

$[Co(NH_3)_5Cl]Cl_2$

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(D) The reaction with $AgNO_3$ indicates that there are $2 \ mol$ of ionizable $Cl^-$ ions outside the coordination sphere.This is represented as $[Co(NH_3)_5Cl]Cl_2$.Upon dissociation,it gives $[Co(NH_3)_5Cl]^{2+} + 2Cl^-$,resulting in a total of $3 \ mol$ of ions ($1 \ mol$ of complex cation + $2 \ mol$ of chloride anions).Therefore,the correct formula is $[Co(NH_3)_5Cl]Cl_2$.

An aqueous solution of $1 \ mol$ of the coordination compound $[Co(NH_3)_5Cl_3]$ gives $3 \ mol$ of ions. If $1 \ mol$ of the same compound reacts with $2 \ mol$ of $AgNO_3$ to produce $2 \ mol$ of $AgCl_{(s)}$,what is the correct formula of the coordination compound?

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