The electronic configurations of Cr^{2+},Mn^{ | vedclass

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(D) The paramagnetic character depends on the number of unpaired electrons $(n)$.For $H_2O$ as a weak field ligand,the number of unpaired electrons in

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$[Co(H_2O)_6]^{2+}$

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(D) The paramagnetic character depends on the number of unpaired electrons $(n)$.For $H_2O$ as a weak field ligand,the number of unpaired electrons in these high-spin octahedral complexes are:$Cr^{2+} (d^4): t_{2g}^3 e_g^1, n = 4$$Mn^{2+} (d^5): t_{2g}^3 e_g^2, n = 5$$Fe^{2+} (d^6): t_{2g}^4 e_g^2, n = 4$$Co^{2+} (d^7): t_{2g}^5 e_g^2, n = 3$Since $[Co(H_2O)_6]^{2+}$ has the minimum number of unpaired electrons $(n = 3)$,it exhibits the minimum paramagnetic character.

List-$I$ (Complex ion)	List-$II$ (Calculated spin only magnetic moment $(BM)$)
$A$. $[Cr(H_2O)_6]^{2+}$	$I$. $3.87$
$B$. $[Co(H_2O)_6]^{2+}$	$II$. $5.92$
$C$. $[Cu(H_2O)_6]^{2+}$	$III$. $4.90$
$D$. $[Mn(H_2O)_6]^{2+}$	$IV$. $1.73$

The electronic configurations of $Cr^{2+}$,$Mn^{2+}$,$Fe^{2+}$,and $Co^{2+}$ ions are $d^4$,$d^5$,$d^6$,and $d^7$ respectively. Which of the following complexes has the minimum paramagnetic character?

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