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(C) The complex is $CrCl_3 \cdot 6H_2O$. When $AgNO_3$ is added,only the chloride ions $(Cl^-)$ present outside the coordination sphere (ionizable) wi

Vedclass · Accepted Answer

$[CrCl_2(H_2O)_4]Cl \cdot 2H_2O$

Vedclass · Answer

(C) The complex is $CrCl_3 \cdot 6H_2O$. When $AgNO_3$ is added,only the chloride ions $(Cl^-)$ present outside the coordination sphere (ionizable) will react to form $AgCl$ precipitate. Given that $1/3$ of the total chlorine is precipitated,it means $1$ out of $3$ chlorine atoms is outside the coordination sphere. Therefore,the formula must be $[CrCl_2(H_2O)_4]Cl \cdot 2H_2O$. This structure contains $1$ ionizable $Cl^-$ ion.

If $1/3$ of the total chlorine in the compound is precipitated on adding $AgNO_3$ to its aqueous solution,which of the following is the correct structure of $CrCl_3 \cdot 6H_2O$?

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