The theoretical value of the magnetic moment | vedclass

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(B) In $[Co(NH_3)_6]^{2+}$,the oxidation state of $Co$ is $+2$.The electronic configuration of $Co^{2+}$ is $[Ar] 3d^7$.In the presence of the strong

Vedclass · Accepted Answer

$1.73$

Vedclass · Answer

(B) In $[Co(NH_3)_6]^{2+}$,the oxidation state of $Co$ is $+2$.The electronic configuration of $Co^{2+}$ is $[Ar] 3d^7$.In the presence of the strong field ligand $NH_3$,the electrons in the $3d$ orbitals rearrange to form a low-spin complex.Specifically,the $3d$ electrons pair up such that there is $1$ unpaired electron remaining.The magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.For $n = 1$,$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ B.M.$

The theoretical value of the magnetic moment for the complex ion $[Co(NH_3)_6]^{2+}$ is ...... $B.M.$

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