Generally,$FeCl_3 \cdot 6H_2O$ is represented as:

  • A
    $trans-[Fe(H_2O)_2Cl_2]Cl \cdot 4H_2O$
  • B
    $trans-[Fe(H_2O)_6]Cl_3$
  • C
    $trans-[Fe(H_2O)_4Cl_2]Cl \cdot 2H_2O$
  • D
    $trans-[Fe(H_2O)_3Cl_3] \cdot 3H_2O$

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Addition of excess aqueous ammonia to a pink coloured aqueous solution of $MCl_2 \cdot 6H_2O (X)$ and $NH_4Cl$ gives an octahedral complex $Y$ in the presence of air. In aqueous solution,complex $Y$ behaves as a $1:3$ electrolyte. The reaction of $X$ with excess $HCl$ at room temperature results in the formation of a blue coloured complex $Z$. The calculated spin-only magnetic moment of $X$ and $Z$ is $3.87 \ B.M.$,whereas it is zero for complex $Y$.
Among the following options,which statement$(s)$ is(are) correct?
$[A]$ The hybridization of the central metal ion in $Y$ is $d^2sp^3$
$[B]$ $Z$ is a tetrahedral complex
$[C]$ Addition of silver nitrate to $Y$ gives only two equivalents of silver chloride
$[D]$ When $X$ and $Z$ are in equilibrium at $0^{\circ}C$,the colour of the solution is pink

Which of the following statements is $NOT$ correct regarding the complex $[Co(NH_3)_6]^{3+}$?

According to valence bond theory,the metal atom or ion can make use of which of the following orbitals to yield hybrid orbitals that can form bonds with ligands?

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