Write the correct order of wavelength of abso | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The wavelength of absorption $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.$\lambda \propto \frac{1}{\D

Vedclass · Accepted Answer

$[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$

Vedclass · Answer

(A) The wavelength of absorption $(\lambda)$ is inversely proportional to the crystal field splitting energy $(\Delta_o)$.$\lambda \propto \frac{1}{\Delta_o}$.According to the spectrochemical series,the strength of ligands is $H_2O Therefore,the crystal field splitting energy follows the order: $[Ni(H_2O)_6]^{2+} Consequently,the wavelength of absorption follows the reverse order: $[Ni(NO_2)_6]^{4-} < [Ni(NH_3)_6]^{2+} < [Ni(H_2O)_6]^{2+}$.

Write the correct order of wavelength of absorption in the visible region for the following complexes:

Similar Questions

Which of the following spectrochemical series is correct?

According to crystal field theory,the $M-L$ bond in a complex is

Consider the following complexes:
$[CoCl(NH_3)_5]^{2+},$ $[Co(CN)_6]^{3-}$
$(A)$ $(B)$
$[Co(NH_3)_5(H_2O)]^{3+},$ $[Cu(H_2O)_4]^{2+}$
$(C)$ $(D)$
The correct order of $A, B, C,$ and $D$ in terms of the wavenumber of light absorbed is:

What is the electronic arrangement of a metal atom/ion in an octahedral complex with a $d^4$ configuration,if $\Delta_o < \text{pairing energy}$?

Three complexes,$[CoCl(NH_3)_5]^{2+} (I)$,$[Co(NH_3)_5H_2O]^{3+} (II)$ and $[Co(NH_3)_6]^{3+} (III)$ absorb light in the visible region. The correct order of the wavelength of light absorbed by them is

Vedclass Test Series

Exam Paper Generator

Online Exam Module