Which of the following coordination compounds | vedclass

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Question

(C) Optical isomerism is exhibited by coordination compounds that lack a plane of symmetry or a center of inversion (chiral molecules).$1$. $[Co(en)_3

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$[Co(NH_3)_3Cl_3]$

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(C) Optical isomerism is exhibited by coordination compounds that lack a plane of symmetry or a center of inversion (chiral molecules).$1$. $[Co(en)_3]^{3+}$: This is a tris-chelated complex of the type $[M(AA)_3]$,which is chiral and shows optical isomerism.$2$. $[Co(en)_2Cl_2]^{+}$: The cis-isomer of this complex lacks a plane of symmetry and is optically active.$3$. $[Co(NH_3)_3Cl_3]$: This complex exists in facial $(fac)$ and meridional $(mer)$ forms. Both the $fac$ and $mer$ isomers of $[Co(NH_3)_3Cl_3]$ possess planes of symmetry,making them achiral and optically inactive.$4$. $[Co(en)(NH_3)_2Cl_2]^{+}$: This complex can exist in chiral forms depending on the arrangement of ligands.Therefore,$[Co(NH_3)_3Cl_3]$ does not exhibit optical isomerism.

List-$I$ (Complex)	List-$II$ (Spin only magnetic moment in $B$.$M$.)
$A$. $[Cr(NH_3)_6]^{3+}$	$I$. $4.90$
$B$. $[NiCl_4]^{2-}$	$II$. $3.87$
$C$. $[CoF_6]^{3-}$	$III$. $0.0$
$D$. $[Ni(CN)_4]^{2-}$	$IV$. $2.83$

Which of the following coordination compounds does not exhibit optical isomerism?

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