The effective atomic number of [A(NH_3)_6]Cl_ | vedclass

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(C) The effective atomic number $(EAN)$ is calculated using the formula: $EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.In

Vedclass · Accepted Answer

$24$

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(C) The effective atomic number $(EAN)$ is calculated using the formula: $EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.In $[A(NH_3)_6]Cl_3$,the oxidation state of $A$ is $+3$ and the coordination number is $6$.Given $EAN = 33$,we have: $33 = Z - 3 + 2(6)$.$33 = Z - 3 + 12$.$33 = Z + 9$.$Z = 33 - 9 = 24$.

The effective atomic number of $[A(NH_3)_6]Cl_3$ is $33$. What is the atomic number of element $A$?

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