For a transition metal with a d^7 configurati | vedclass

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Question

(A) The magnetic moment $(\mu)$ is calculated using the spin-only formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.

Vedclass · Accepted Answer

$3.87$

Vedclass · Answer

(A) The magnetic moment $(\mu)$ is calculated using the spin-only formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.
For a $d^7$ configuration in a high-spin octahedral field,the electrons are distributed as $t_{2g}^5 e_g^2$,resulting in $n = 3$ unpaired electrons.
Substituting $n = 3$ into the formula: $\mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \ B.M.$

For a transition metal with a $d^7$ configuration,the magnetic susceptibility (magnetic moment) is ........ $B.M.$

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