(B) In the complex ion $[Cu(NH_3)_4]^{2+}$,let the oxidation state of $Cu$ be $x$.Since $NH_3$ is a neutral ligand,its oxidation state is $0$.The tota

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(B) In the complex ion $[Cu(NH_3)_4]^{2+}$,let the oxidation state of $Cu$ be $x$.Since $NH_3$ is a neutral ligand,its oxidation state is $0$.The total charge on the complex ion is $+2$.Therefore,$x + 4(0) = +2$.$x = +2$.Thus,the oxidation state of copper is $+2$.