What is the angle of inclination of the tange | vedclass

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(C) Given the equation of the curve is $y = (x - 1)(x - 2) = x^2 - 3x + 2$.To find the slope of the tangent,we differentiate with respect to $x$:$\fra

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$3\pi /4$

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(C) Given the equation of the curve is $y = (x - 1)(x - 2) = x^2 - 3x + 2$.To find the slope of the tangent,we differentiate with respect to $x$:$\frac{dy}{dx} = 2x - 3$.Now,evaluate the slope at the point $(1, 0)$:$m = \left( \frac{dy}{dx} ight)_{(1, 0)} = 2(1) - 3 = -1$.The slope of the tangent is equal to $	an(\psi)$,where $\psi$ is the angle of inclination with the $x$-axis.$	an(\psi) = -1$.Since $	an(\psi) = -1$,the angle $\psi = \pi - \frac{\pi}{4} = \frac{3\pi}{4}$.

What is the angle of inclination of the tangent to the curve $y = (x - 1)(x - 2)$ at the point $(1, 0)$ with the $x$-axis?

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