The resistance is 10.845 Omega and the curre | vedclass

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(B) According to the rules of significant figures,when multiplying two numbers,the result should have the same number of significant figures as the nu

Vedclass · Accepted Answer

$35.0$

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(B) According to the rules of significant figures,when multiplying two numbers,the result should have the same number of significant figures as the number with the least number of significant figures.Here,the resistance $R = 10.845 \ \Omega$ has $5$ significant figures.The current $I = 3.23 \ A$ has $3$ significant figures.The product $V = I 	imes R = 3.23 	imes 10.845 = 35.02935 \ V$.The result must be rounded to $3$ significant figures.Rounding $35.02935$ to $3$ significant figures gives $35.0 \ V$.

List-$I$ (Number)	List-$II$ (Significant figures)
$A. 1001$	$I. 3$
$B. 010.1$	$II. 4$
$C. 100.100$	$III. 5$
$D. 0.0010010$	$IV. 6$

The resistance is $10.845 \ \Omega$ and the current is $3.23 \ A$. The voltage is $35.02935 \ V$. Express the result in appropriate significant figures. (in $V$)

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List-$I$ (Number) List-$II$ (Significant figures)

$A. 1001$ $I. 3$

$B. 010.1$ $II. 4$

$C. 100.100$ $III. 5$

$D. 0.0010010$ $IV. 6$

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