(C) The relationship between force $F$ and potential energy $U$ is given by $F = -\frac{dU}{dx}$.For the interval $0 < x < a$,the potential energy $U(

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(C) The relationship between force $F$ and potential energy $U$ is given by $F = -\frac{dU}{dx}$.For the interval $0 0$. Thus,$F = -\frac{d}{dx}(kx) = -k$,which is a constant negative value.For $x > a$,the potential energy $U(x)$ is constant,so $\frac{dU}{dx} = 0$,which implies $F = 0$.Comparing this with the given options,the graph that shows a constant negative force for $0 a$ is graph $C$.

Class 11 Physics Work, Energy and Power Conservative and Non-Conservative forces and Potential Energy

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The potential energy graph of a particle is given. Find the corresponding force graph.

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Work, Energy and Power

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Conservative and Non-Conservative forces and Potential Energy

In the case of non-conservative forces,the following statement is correct.

MediumAP EAMCET 2023

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The variation of potential energy $U$ of a system is shown in the figure. The force acting on the system is best represented by:

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$Assertion$ : Frictional forces are conservative forces.
$Reason$ : Potential energy can be associated with frictional forces.

EasyAIIMS 2005

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$A$ particle is acted upon by a force given by $F=-\alpha x^3-\beta x^4$,where $\alpha$ and $\beta$ are positive constants. At the point $x=0$,the particle is

DifficultKVPY 2012

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The potential energy for a force field $\vec{F}$ is given by $U(x,y) = \cos(x + y)$. The force acting on a particle at the position given by coordinates $(0, \frac{\pi}{4})$ is

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The potential energy graph of a particle is given. Find the corresponding force graph.

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In the case of non-conservative forces,the following statement is correct.

The variation of potential energy $U$ of a system is shown in the figure. The force acting on the system is best represented by:

$Assertion$ : Frictional forces are conservative forces.$Reason$ : Potential energy can be associated with frictional forces.

$A$ particle is acted upon by a force given by $F=-\alpha x^3-\beta x^4$,where $\alpha$ and $\beta$ are positive constants. At the point $x=0$,the particle is

The potential energy for a force field $\vec{F}$ is given by $U(x,y) = \cos(x + y)$. The force acting on a particle at the position given by coordinates $(0, \frac{\pi}{4})$ is

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$Assertion$ : Frictional forces are conservative forces.
$Reason$ : Potential energy can be associated with frictional forces.