(C) The impulse $J$ is defined as the product of force $F$ and the time interval $\Delta t$ for which it acts: $J = F \times \Delta t$. Given: Force $

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$1.5 \times 10^{-3} \, N \cdot s$

(C) The impulse $J$ is defined as the product of force $F$ and the time interval $\Delta t$ for which it acts: $J = F \times \Delta t$. Given: Force $F = 50 \, dynes$. Since $1 \, N = 10^5 \, dynes$,we convert the force to $SI$ units: $F = 50 \times 10^{-5} \, N = 5 \times 10^{-4} \, N$. Time $\Delta t = 3 \, s$. Impulse $J = (5 \times 10^{-4} \, N) \times (3 \, s) = 15 \times 10^{-4} \, N \cdot s = 1.5 \times 10^{-3} \, N \cdot s$.

Class 11 Physics Newton's Laws of Motion and Friction Third Law of Motion and Momentum and Impulse

Medium

$A$ force of $50 \, dynes$ acts on a particle of mass $5 \, g$ for $3 \, seconds$. What is the impulse of the force?

A
$0.15 \times 10^{-3} \, N \cdot s$
B
$0.98 \times 10^{-3} \, N \cdot s$
C
$1.5 \times 10^{-3} \, N \cdot s$
D
$2.5 \times 10^{-3} \, N \cdot s$

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Newton's Laws of Motion and Friction

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Third Law of Motion and Momentum and Impulse

$A$ body of mass $50 \, g$ has a velocity of $20 \, cm/s$. If a constant force of $50 \, dyne$ acts on it,what will be its momentum after $5 \, s$?

Medium

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$A$ body of mass $M$ hits normally a rigid wall with velocity $V$ and bounces back with the same velocity. The impulse experienced by the body is

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The figure below shows the position-time graph of a body of mass $0.04 \; kg$. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the body? What is the magnitude of each impulse?

Easy

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Two trains $A$ and $B$ are running in the same direction on parallel rails such that $A$ is faster than $B$. Packets of equal weight are transferred between them. What will happen due to this?

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In the figure,the position-time graph of a particle of mass $0.1\, kg$ is shown. The impulse at $t = 2\, s$ is ......... $kg\, m/s$.

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$A$ force of $50 \, dynes$ acts on a particle of mass $5 \, g$ for $3 \, seconds$. What is the impulse of the force?

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$A$ body of mass $50 \, g$ has a velocity of $20 \, cm/s$. If a constant force of $50 \, dyne$ acts on it,what will be its momentum after $5 \, s$?

$A$ body of mass $M$ hits normally a rigid wall with velocity $V$ and bounces back with the same velocity. The impulse experienced by the body is

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Two trains $A$ and $B$ are running in the same direction on parallel rails such that $A$ is faster than $B$. Packets of equal weight are transferred between them. What will happen due to this?

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