If the mass of block B is 3,kg and the mass o | vedclass

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(B) For a system where block $A$ is on a smooth horizontal surface and block $B$ is hanging vertically connected by a string over a pulley:The force c

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$3$

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(B) For a system where block $A$ is on a smooth horizontal surface and block $B$ is hanging vertically connected by a string over a pulley:The force causing the system to accelerate is the weight of block $B$,which is $m_B g$.The total mass being accelerated is $(m_A + m_B)$.Using Newton's second law,$F_{net} = m_{total} a$.$m_B g = (m_A + m_B) a$$a = \frac{m_B g}{m_A + m_B}$Given $m_A = 7\,kg$,$m_B = 3\,kg$,and $g = 10\,m/s^2$:$a = \frac{3 	imes 10}{7 + 3} = \frac{30}{10} = 3\,m/s^2$.

If the mass of block $B$ is $3\,kg$ and the mass of block $A$ is $7\,kg$,then the acceleration of the system is ........... $m/s^2$. $(g = 10\,m/s^2)$

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