Two weights W_1 and W_2 are tied to a massles | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The tension in a string over a pulley with masses $m_1$ and $m_2$ in a stationary frame is given by $T = \frac{2m_1m_2}{m_1 + m_2}g$.When the pull

Vedclass · Accepted Answer

$\frac{4W_1W_2}{W_1 + W_2}$

Vedclass · Answer

(A) The tension in a string over a pulley with masses $m_1$ and $m_2$ in a stationary frame is given by $T = \frac{2m_1m_2}{m_1 + m_2}g$.When the pulley is accelerated upwards with acceleration $a$,the effective acceleration due to gravity becomes $g_{eff} = g + a$.Given $a = g$,the effective acceleration is $g_{eff} = g + g = 2g$.Substituting this into the tension formula:$T = \frac{2m_1m_2}{m_1 + m_2}(2g) = \frac{4m_1m_2}{m_1 + m_2}g$.Since $W = mg$,we can write $m = W/g$.Substituting $m_1 = W_1/g$ and $m_2 = W_2/g$:$T = \frac{4(W_1/g)(W_2/g)}{(W_1/g + W_2/g)}g = \frac{4W_1W_2}{g(W_1 + W_2)}g = \frac{4W_1W_2}{W_1 + W_2}$.

Two weights $W_1$ and $W_2$ are tied to a massless string and passed over a pulley. If the pulley is accelerated upwards with an acceleration $g$,what will be the tension in the string?

Similar Questions

Two blocks of masses $m_1$ and $m_2$ are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with an acceleration $a_0 = g$, then the tension in the string will be

In the system shown in the adjoining figure,the tension $T_2$ is

In the figure given below,with what acceleration will the block of mass $m$ move? (Pulley and strings are massless and frictionless)

Consider a situation in which both the horizontal and vertical surfaces of the block $M_0$ are smooth,as shown in the adjoining figure. $A$ force $F$ is applied to $M_0$. Mark the correct statement$(s)$.

Find the acceleration of block $B$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module