$A$ capillary tube of length $l$ and radius $r$ is connected to the bottom of a container. When the pressure difference across it is $P$,the volume of water flowing out per second is $V$. If another capillary tube of the same length but half the radius is connected in series with the first one,what will be the new volume of liquid flowing out per second? (The total pressure difference across the system is $P$.)

  • A
    $\frac{V}{16}$
  • B
    $\frac{V}{17}$
  • C
    $\frac{16V}{17}$
  • D
    $\frac{17V}{16}$

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