A wooden stick of length 2 m floats on water | vedclass

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(D) The force due to surface tension is given by $F = T 	imes L$,where $T$ is the surface tension and $L$ is the length of the stick.The force exerte

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$0.02$

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(D) The force due to surface tension is given by $F = T 	imes L$,where $T$ is the surface tension and $L$ is the length of the stick.The force exerted by water on one side is $F_1 = T_1 	imes L = 0.07 	imes 2 = 0.14 \ N$.The force exerted by the soap solution on the other side is $F_2 = T_2 	imes L = 0.06 	imes 2 = 0.12 \ N$.The net force acting on the stick is the difference between these two forces:$F_{net} = F_1 - F_2 = 0.14 \ N - 0.12 \ N = 0.02 \ N$.

$A$ wooden stick of length $2 \ m$ floats on water. The surface tension of water is $0.07 \ N/m$. If a soap solution with a surface tension of $0.06 \ N/m$ is applied to one side of the stick,what will be the net force acting on it in $N$?

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