What mass should be suspended from the wire C | vedclass

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(B) liquid film has two surfaces (front and back). The surface tension force acts along the length $l$ on both sides of the wire $CD$.Therefore,the to

Vedclass · Accepted Answer

$\frac{2Tl}{g}$

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(B) liquid film has two surfaces (front and back). The surface tension force acts along the length $l$ on both sides of the wire $CD$.Therefore,the total upward force due to surface tension is $F = T 	imes l + T 	imes l = 2Tl$.For the wire $CD$ to be in equilibrium,the downward gravitational force must balance this upward surface tension force.$mg = 2Tl$$m = \frac{2Tl}{g}$

What mass should be suspended from the wire $CD$ to keep it in equilibrium?

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