What is the slope of the line AB in the given | vedclass

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(B) The relationship between Celsius $(C)$ and Fahrenheit $(F)$ scales is given by the formula: $C = \frac{5}{9}(F - 32)$.This can be rewritten as: $C

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$5/9$

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(B) The relationship between Celsius $(C)$ and Fahrenheit $(F)$ scales is given by the formula: $C = \frac{5}{9}(F - 32)$.This can be rewritten as: $C = \frac{5}{9}F - \frac{160}{9}$.Comparing this with the equation of a straight line $y = mx + c$,where $y$ is the temperature in Celsius and $x$ is the temperature in Fahrenheit,the slope $m$ is the coefficient of $F$.Therefore,the slope $m = \frac{5}{9}$.Alternatively,using the coordinates of points $A$ and $B$ from the graph:Point $A$ is $(32, 0)$ and point $B$ is $(212, 100)$.Slope $m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{100 - 0}{212 - 32} = \frac{100}{180} = \frac{5}{9}$.

What is the slope of the line $AB$ in the given graph?

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