The kinetic energy of 20 , L of {H_2} gas is | vedclass

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(D) Given: Kinetic energy $E = 1.5 	imes 10^5 \, J$ and Volume $V = 20 \, L = 20 	imes 10^{-3} \, m^3$.The relationship between pressure $P$,kinetic

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$5 	imes 10^6 \, N/m^2$

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(D) Given: Kinetic energy $E = 1.5 	imes 10^5 \, J$ and Volume $V = 20 \, L = 20 	imes 10^{-3} \, m^3$.The relationship between pressure $P$,kinetic energy $E$,and volume $V$ for an ideal gas is given by $P = \frac{2}{3} \frac{E}{V}$.Substituting the values:$P = \frac{2}{3} \left( \frac{1.5 	imes 10^5}{20 	imes 10^{-3}} ight)$$P = \frac{2}{3} 	imes \frac{1.5}{20} 	imes 10^8$$P = \frac{2}{3} 	imes 0.075 	imes 10^8$$P = 0.05 	imes 10^8 = 5 	imes 10^6 \, N/m^2$.

The kinetic energy of $20 \, L$ of ${H_2}$ gas is $1.5 \times 10^5 \, J$. Find the pressure exerted on the container.

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