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(B) The average velocity of a gas molecule is given by the formula $v_{av} = \sqrt{\frac{8kT}{\pi m}}$,where $k$ is the Boltzmann constant,$T$ is the

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$V_1$

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(B) The average velocity of a gas molecule is given by the formula $v_{av} = \sqrt{\frac{8kT}{\pi m}}$,where $k$ is the Boltzmann constant,$T$ is the absolute temperature,and $m$ is the mass of one molecule of the gas.Since the temperature $T$ is the same for all vessels,the average velocity of a specific gas depends only on its molecular mass $m$.In vessel $A$,the average velocity of $O_2$ is $V_1 = \sqrt{\frac{8kT}{\pi m_{O_2}}}$.In vessel $C$,the $O_2$ molecules are at the same temperature $T$ and have the same molecular mass $m_{O_2}$ as in vessel $A$.The presence of $N_2$ in the mixture in vessel $C$ does not affect the individual average velocity of the $O_2$ molecules.Therefore,the average velocity of $O_2$ in vessel $C$ remains $V_1$.

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