The number of molecules in 1 , cm^{3} of an i | vedclass

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(A) At $N.T.P.$,the molar volume of an ideal gas is $22.4 \, L$. Since $1 \, L = 1000 \, cm^{3}$,the volume of $1 \, mole$ of gas is $22.4 	imes 10^{

Vedclass · Accepted Answer

$6.02 	imes 10^{23} / 22400$

Vedclass · Answer

(A) At $N.T.P.$,the molar volume of an ideal gas is $22.4 \, L$. Since $1 \, L = 1000 \, cm^{3}$,the volume of $1 \, mole$ of gas is $22.4 	imes 10^{3} \, cm^{3} = 22400 \, cm^{3}$. According to Avogadro's hypothesis,$1 \, mole$ of any gas contains $6.023 	imes 10^{23}$ molecules. Therefore,the number of molecules in $22400 \, cm^{3}$ is $6.023 	imes 10^{23}$. Thus,the number of molecules in $1 \, cm^{3}$ is $\frac{6.023 	imes 10^{23}}{22400}$.

The number of molecules in $1 \, cm^{3}$ of an ideal gas at $N.T.P.$ is:

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