$A$ wave with a frequency of $100 \, Hz$ has a velocity of $10 \, m/s$. What is the phase difference between two particles separated by a distance of $2.5 \, cm$?

Write the definition of wave speed and derive $v = \frac{\omega}{k}$.

$A$ plane wave $y = A \sin \omega \left( t - \frac{x}{v} \right)$ undergoes normal incidence on a plane boundary separating medium $M_1$ and $M_2$ and splits into a reflected and transmitted wave having speeds $v_1$ and $v_2$. Then:

$A$ sine wave has an amplitude $A$ and wavelength $\lambda$. Let $V$ be the wave velocity and $v$ be the maximum velocity of a particle in the medium. Then:

The equation of a wave travelling along the positive $x$-axis,as shown in the figure at $t = 0$,is given by:

$A$ longitudinal wave is represented by $x = 10 \sin 2 \pi (nt - \frac{x}{\lambda}) \, cm$. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to .....................