Two tuning forks A and B are sounded together | vedclass

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(C) The initial beat frequency is $f_{beat} = |n_A - n_B| = 4 \,Hz$.Given $n_A = 320 \,Hz$,the possible frequencies for $B$ are $n_B = 320 \pm 4$,whic

Vedclass · Accepted Answer

$324$

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(C) The initial beat frequency is $f_{beat} = |n_A - n_B| = 4 \,Hz$.Given $n_A = 320 \,Hz$,the possible frequencies for $B$ are $n_B = 320 \pm 4$,which are $324 \,Hz$ or $316 \,Hz$.When a tuning fork is loaded with wax,its frequency decreases.If $n_B$ was $316 \,Hz$,loading it would decrease the frequency further away from $320 \,Hz$,increasing the beat frequency (e.g.,to $5$ or $6 \,Hz$).If $n_B$ was $324 \,Hz$,loading it would decrease the frequency towards $320 \,Hz$,which would decrease the beat frequency. However,the problem states the beat frequency remains $4 \,Hz$. This implies the frequency was $324 \,Hz$ and it decreased to a value where the beat frequency is still $4 \,Hz$ (or the question implies the initial state). Given the options,$324 \,Hz$ is the correct frequency for $B$.

Two tuning forks $A$ and $B$ are sounded together and produce $4$ beats per second. The frequency of tuning fork $A$ is $320 \,Hz$. When tuning fork $B$ is loaded with wax,the number of beats per second remains $4$. What is the frequency of tuning fork $B$ in $Hz$?

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