A solid sphere of mass 1 gm contains 5 times | vedclass

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(A) The total number of atoms is $N = 5 	imes 10^{21}$.The number of atoms from which one electron is removed is $n = 0.01\% 	ext{ of } N$.$n = \fra

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$+ 0.08$

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(A) The total number of atoms is $N = 5 	imes 10^{21}$.The number of atoms from which one electron is removed is $n = 0.01\% 	ext{ of } N$.$n = \frac{0.01}{100} 	imes 5 	imes 10^{21} = 10^{-4} 	imes 5 	imes 10^{21} = 5 	imes 10^{17}$.Since one electron is removed from each of these atoms,the total number of electrons removed is $n = 5 	imes 10^{17}$.The charge acquired by the sphere due to the removal of electrons is $Q = +ne$.$Q = (5 	imes 10^{17}) 	imes (1.6 	imes 10^{-19} \ C)$.$Q = 8 	imes 10^{-2} \ C = 0.08 \ C$.Since electrons are removed,the sphere becomes positively charged,so $Q = +0.08 \ C$.

$A$ solid sphere of mass $1 \ gm$ contains $5 \times 10^{21}$ atoms. If one electron is removed from every $0.01\%$ of the atoms,what is the charge acquired by the sphere in $C$?

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