At which point is the electric field maximum?

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(B) The electric field $E$ is related to the potential gradient by the relation $E = -\frac{dV}{dr}$.This implies that the electric field is inversely

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$A$

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(B) The electric field $E$ is related to the potential gradient by the relation $E = -\frac{dV}{dr}$.This implies that the electric field is inversely proportional to the distance between the equipotential surfaces,i.e.,$E \propto \frac{1}{dr}$.Looking at the provided equipotential lines,the distance between the equipotential surfaces is smallest near point $A$ (where the lines are most crowded).Since the lines are closest together at point $A$,the potential gradient is steepest,and therefore the electric field is maximum at point $A$.

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