Two identical charges $Q$ are separated by a distance $r$. $A$ third charge $q$ is placed at the midpoint of the line joining the two charges such that all three charges are in equilibrium. In this state,$q = $ . . . . . . .

  • A
    $ - \frac{Q}{2} $
  • B
    $ - \frac{Q}{4} $
  • C
    $ + \frac{Q}{4} $
  • D
    $ + \frac{Q}{2} $

Explore More

Similar Questions

$A$ cube of side $b$ has a charge $q$ at each of its vertices. The electric field due to this charge distribution at the centre of this cube will be

Three point charges are placed at the corners of an equilateral triangle of side $L$ as shown in the figure.

Difficult
View Solution

Three point charges $q_1, q_2, q_3$ are placed at the vertices of a triangle. If the forces on $q_1$ and $q_2$ are $(2\hat{i} - \hat{j}) \, N$ and $(\hat{i} + 3\hat{j}) \, N$,respectively,then what will be the force on $q_3$?

The repulsive force between two point charges is $F$ when they are separated by a distance of $1 \, m$. Now,these point charges are replaced by spheres of radius $25 \, cm$ having the same charges. The distance between their centers is $1 \, m$. The repulsive force in the two cases will decrease according to:

Which of the following physical quantities have the same dimensions?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo