A 4 mu F capacitor is charged to 400 V and th | vedclass

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(D) When a charged capacitor is connected to a resistor,the total energy stored in the capacitor is dissipated as heat in the resistor.The energy stor

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$0.32$

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(D) When a charged capacitor is connected to a resistor,the total energy stored in the capacitor is dissipated as heat in the resistor.The energy stored in a capacitor is given by the formula $U = \frac{1}{2}CV^2$.Given:Capacitance $C = 4\ \mu F = 4 	imes 10^{-6}\ F$Voltage $V = 400\ V$Substituting the values:$U = \frac{1}{2} 	imes (4 	imes 10^{-6}) 	imes (400)^2$$U = 2 	imes 10^{-6} 	imes 160000$$U = 2 	imes 10^{-6} 	imes 1.6 	imes 10^5$$U = 3.2 	imes 10^{-1} = 0.32\ J$.Thus,the total heat energy produced is $0.32\ J$.

$A$ $4\ \mu F$ capacitor is charged to $400\ V$ and then connected to a $1\ k\Omega$ resistor. How much heat energy in $J$ is produced?

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