We need to connect a capacitor of 16 mu F, 10 | vedclass

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Question

(C) Given: Required capacitance $C' = 16\ \mu F$,Required voltage $V' = 1000\ V$. Available capacitance $C = 8\ \mu F$,Available voltage $V = 250\ V$.

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(C) Given: Required capacitance $C' = 16\ \mu F$,Required voltage $V' = 1000\ V$. Available capacitance $C = 8\ \mu F$,Available voltage $V = 250\ V$.To achieve the required voltage $V'$,we need to connect $n$ capacitors in series: $n = V' / V = 1000 / 250 = 4$.Now,the equivalent capacitance of $n$ capacitors in series is $C_{eq} = C / n = 8 / 4 = 2\ \mu F$.To achieve the required capacitance $C'$,we need to connect $m$ such series branches in parallel: $m = C' / C_{eq} = 16 / 2 = 8$.Total number of capacitors required = $m 	imes n = 8 	imes 4 = 32$.

We need to connect a capacitor of $16\ \mu F, 1000\ V$. However,we only have capacitors of $8\ \mu F, 250\ V$ available. How many such capacitors are required?

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