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(B) $1$. When $n$ capacitors of capacitance $C$ are connected in parallel to a battery of voltage $V$,each capacitor stores a charge $q = CV$.$2$. Tot

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(B) $1$. When $n$ capacitors of capacitance $C$ are connected in parallel to a battery of voltage $V$,each capacitor stores a charge $q = CV$.$2$. Total charge on each capacitor remains $q = CV$ after disconnection.$3$. When these $n$ capacitors are connected in series,the total voltage $V'$ across the series combination is the sum of the voltages across each capacitor.$4$. Since each capacitor has charge $q = CV$ and capacitance $C$,the voltage across each capacitor is $V_i = q/C = (CV)/C = V$.$5$. For $n = 10$ capacitors in series,the total voltage $V' = n 	imes V = 10V$.

Ten capacitors are connected in parallel to a battery of $V$ volts. If all capacitors are disconnected from the battery and then connected in series,what will be the voltage across the combination in terms of $V$ (in $V$)?

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