In the given circuit,what are the electric po | vedclass

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(B) The circuit consists of four identical capacitors $C$ connected in series across a $10 \, V$ $DC$ source. Since the capacitors are identical and i

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$7.5 \, V, -2.5 \, V$

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(B) The circuit consists of four identical capacitors $C$ connected in series across a $10 \, V$ $DC$ source. Since the capacitors are identical and in series,the potential difference across each capacitor is equal. Let the potential difference across each capacitor be $V_c$. $V_c = \frac{10 \, V}{4} = 2.5 \, V$. Point $N$ is grounded,so its potential $V_N = 0 \, V$. Moving from $N$ towards $A$ across three capacitors,the potential increases: $V_A - V_N = 3 	imes 2.5 \, V = 7.5 \, V$. Since $V_N = 0 \, V$,we get $V_A = 7.5 \, V$. Moving from $N$ towards $B$ across one capacitor,the potential decreases: $V_N - V_B = 2.5 \, V$. Since $V_N = 0 \, V$,we get $0 - V_B = 2.5 \, V$,which implies $V_B = -2.5 \, V$. Thus,the potentials at $A$ and $B$ are $7.5 \, V$ and $-2.5 \, V$ respectively.

In the given circuit,what are the electric potentials at points $A$ and $B$?

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