A total of 100 cells,each having an emf of 5, | vedclass

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(A) Let $n$ be the number of cells in each row and $m$ be the number of rows.Total number of cells $N = m 	imes n = 100$  --- $(i)$For maximum curren

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$2$

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(A) Let $n$ be the number of cells in each row and $m$ be the number of rows.Total number of cells $N = m 	imes n = 100$  --- $(i)$For maximum current in a mixed grouping of cells,the external resistance $R$ must be equal to the equivalent internal resistance of the battery combination.$R = \frac{n 	imes r}{m}$,where $r$ is the internal resistance of one cell.Given $R = 25\,\Omega$ and $r = 1\,\Omega$,we have:$25 = \frac{n 	imes 1}{m} \Rightarrow n = 25m$  --- $(ii)$Substituting $(ii)$ into $(i)$:$m 	imes (25m) = 100$$25m^2 = 100$$m^2 = 4$$m = 2$Thus,the number of rows should be $2$.

$A$ total of $100$ cells,each having an $emf$ of $5\,V$ and an internal resistance of $1\,\Omega$,are connected to an external resistance of $25\,\Omega$ to obtain the maximum current. If each row contains an equal number of cells,what should be the number of rows?

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