A coil of 100 , W, 220 , V is cut into two eq | vedclass

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(B) The resistance of the original coil is $R = \frac{V^2}{P} = \frac{220^2}{100} = 484 \, \Omega$.When the coil is cut into two equal parts,the resis

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$400$

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(B) The resistance of the original coil is $R = \frac{V^2}{P} = \frac{220^2}{100} = 484 \, \Omega$.When the coil is cut into two equal parts,the resistance of each part becomes $R' = \frac{R}{2} = 242 \, \Omega$.When these two parts are connected in parallel,the equivalent resistance is $R_{eq} = \frac{R' 	imes R'}{R' + R'} = \frac{R'}{2} = \frac{R}{4} = \frac{484}{4} = 121 \, \Omega$.The power consumed in the parallel combination is $P' = \frac{V^2}{R_{eq}} = \frac{220^2}{121} = \frac{48400}{121} = 400 \, W$.Since $H = P' 	imes t$,for $t = 1 \, sec$,the heat produced is $H = 400 	imes 1 = 400 \, J$.

$A$ coil of $100 \, W, 220 \, V$ is cut into two equal parts and connected in parallel. How much heat in $J$ is produced in $1 \, sec$?

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