$A$ current $i$ flows in a horizontal square loop of side $L$. Now,half of the loop is folded to be vertical. If $\overrightarrow {{\mu _1}}$ and $\overrightarrow {{\mu _2}}$ are the magnetic moments before and after folding,respectively,then:

• A
  $\overrightarrow {{\mu _2}} = 0$
• B
  $\overrightarrow {{\mu _1}}$ and $\overrightarrow {{\mu _2}}$ are in the same direction
• C
  $\frac{{|\overrightarrow {{\mu _1}} |}}{{|\overrightarrow {{\mu _2}} |}} = \sqrt 2 $
• D
  $\frac{{|\overrightarrow {{\mu _1}} |}}{{|\overrightarrow {{\mu _2}} |}} = \frac{1}{{\sqrt 2 }}$