$A$ magnetic rod of length $L$ has a magnetic dipole moment $M$. If it is bent into a semicircle,what will be its new magnetic dipole moment?

$A$ magnetised wire of magnetic moment $3.14 \, A-m^2$ is bent in the form of a semi-circle. The new magnetic moment will be.....$A-m^2$

The following figures show the arrangement of bar magnets in different configurations. Each magnet has a magnetic dipole moment $\vec{m}$. Which configuration has the highest net magnetic dipole moment?

$A$ wire of magnetic moment $M$ is bent to form a circular arc which subtends an angle $90^o$ at the center. Then,its new magnetic moment is:

Two identical thin bar magnets each of length $l$ and pole strength $m$ are placed at right angles to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is:

$A$ straight steel wire of length $\ell$ has a magnetic moment $M$. It is bent into an $L$-shape as shown in the figure. The new magnetic moment is