What is the de Broglie wavelength of an elect | vedclass

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(D) The de Broglie wavelength $\lambda$ for an electron accelerated through a potential difference $V$ is given by the formula: $\lambda = \frac{12.27

Vedclass · Accepted Answer

$1.4$

Vedclass · Answer

(D) The de Broglie wavelength $\lambda$ for an electron accelerated through a potential difference $V$ is given by the formula: $\lambda = \frac{12.27}{\sqrt{V}} \ \mathring A$. Substituting the given value $V = 80 \ V$: $\lambda = \frac{12.27}{\sqrt{80}} \ \mathring A$. Since $\sqrt{80} \approx 8.944$,we have: $\lambda = \frac{12.27}{8.944} \approx 1.371 \ \mathring A$. Rounding to one decimal place,we get $\lambda \approx 1.4 \ \mathring A$.

What is the de Broglie wavelength of an electron accelerated through $80 \ V$ in $\mathring A$?

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